### Trees Of Different Heights

I saw four trees of different heights. Its average height is 74 meters, and the difference amongst the first three trees is two meters. The difference between the third and fourth tree is six meters.

Now can you tell how tall each tree is?

1. I think 1st tree is 70 metres tall,the second 72, the third 74 and fourth Tree 80 metres tall.
Bcoz
70 72 74 80=296
296/4=74

2. Hey,
Avrage is. 74.
And tres is 4.
Then total hight =296.
N gap bitwen 1st 3 tres is two two meter n last or 2nd last is 6.
Then 1st is 70, 2nd is 72, 3rd iz 74 or last wala 80.
Total hight= 70+72+74+80= 296,
N avrage= 296/4= 74,
Simple,
:-)

3. Average is 74 and there are 4 trees
total 296
gap b/w 3 trees is 2 meter and 4th tree is 6
then 1 is 70,2nd 72,74 80 respectiviely
total 296
average 74

4. Let the heights be x, x+2, x+4, x+10
Their average = 74
=> (4x+16)/4=74
=> x=70

So the heights are
70,72,74,80

5. 70, 72, 74 & 80

6. It can also be as,, 75 + 73 + 71 + 77 = 296

7. if the average is 74 and the nomber of trees is 4 then the total heights = 74×4=296 meters and if the gap between the first three trees =2 meters and between the 3rd and 4rth trees=6 meters then if we considered the first tree is 70 meters height then the 2nd is 72 ,3rd is 74 and the 4rth is 80 meters (simply)

8. or if we considered the heights are as followed x and X+2 and X+4 and X+4+6 their average is 74 then (4x+16)/4=74 then x1=70 and X2=72 and X3=74 and X4=80

9. 78m,76m,74m,68m

10. statement:short method compare with 3rd tree.1st tree is 4mts less than third,2nd is two mts less than third,and 4th tree is six mts grater than third
2+4=6
hence balanced
74-4 ,74-2 ,74 ,74+6
=70,72,74,80
or
74+4 ,74+2 ,74 ,74-6
=78,76,74,68 (put lessthan in place of greater than vice versa in above statement)

11. 72,74,76,82.

12. They are 78, 76, 74, and 68 meters.
(x-2+x-4+x-6+x-12)
4x-24=74
(4x-24)/4=74
4x-24=296
4x=320
(4x)/4=320/4
x=80
So replace each x with 80 and you get 78, 76, 74, and 68.