A man passed away leaving 18 cattles for his 3 sons in his will. He directed that the 1st son should have half of all the cattles, the 2nd should have one-third of all the cattles & the 3rd should have one-ninth of all the cattles.
How many cattles will each of the sons have, if no cattle must be killed or cut?
Half=18/2=9, 1/3rd =18/3=6, 1/9th=18/9=2. 2+6+9=17.
9,6,2...
ReplyDelete12,4,1
ReplyDeletefirst the will borrow one cattle
ReplyDeletethen 1/2 of 18=9 1/3=6 and 1/9 =2
Borrow from Where and Who... the answer is correct but one wil remain... who will they give it to.
Delete9 6 2
ReplyDelete9 6 2
ReplyDelete9 6 2
ReplyDelete9 6 2
ReplyDelete9 6 2
ReplyDelete9 6 2
ReplyDelete9 6 3
ReplyDelete9 6 2
ReplyDeletehi admin, i m new to blogs..
ReplyDeleteCould you please insist me creating a blog...?
where is the remaining one !
ReplyDeleteWhere is remaing one ............... Ans-9+6+2+?
ReplyDelete9,6,2
ReplyDeleteThe first son gets 9, the second son gets 6, and the final son gets 1.
ReplyDelete9,6,2
ReplyDelete9-6-2=17
ReplyDeleteIs anyone else going to point out that there is no such thing as a singular "cattle"? I protest this grammatically incorrect problem.
ReplyDeleteThis is an ancient problem: it was different. A man passed away leaving 17 cattles for his 3 sons in his will. He directed that the 1st son should have half of all the cattles, the 2nd should have one-third of all the cattles & the 3rd should have one-ninth of all the cattles. The 3 sons where not able to solve the problem, so they asked to an old man how to solve it. He said "I can give you for a while an other cattle, for free". Consequently they could divide: 9, 6, 2. The total is 17. What to do with the last cattle? They gave back for free to the old man.
ReplyDeletehmmm me too agree with and heard the old riddle
DeleteYa.....Ya the story is amazing......i agree.. :-)
ReplyDelete